Let О”abcв€јо”def And Their Areas Be Respectively 64cmві And 121cmві. If Ef=15.4cm Find Bc. File

For two similar triangles, the ratio of their areas is equal to the square of the ratio of their corresponding sides. This relationship is expressed by the formula:

64121=BC15.4the square root of 64 over 121 end-fraction end-root equals the fraction with numerator cap B cap C and denominator 15.4 end-fraction For two similar triangles, the ratio of their

The length of side BCcap B cap C 1. Identify the relationship between areas and sides Substitute the known values Plug the given areas

BC=811×15.4cap B cap C equals 8 over 11 end-fraction cross 15.4 BC=8×1.4cap B cap C equals 8 cross 1.4 BC=11.2 cmcap B cap C equals 11.2 cm ✅ Final Answer The length of the corresponding side BCcap B cap C For two similar triangles

Area(△ABC)Area(△DEF)=(BCEF)2the fraction with numerator Area open paren triangle cap A cap B cap C close paren and denominator Area open paren triangle cap D cap E cap F close paren end-fraction equals open paren the fraction with numerator cap B cap C and denominator cap E cap F end-fraction close paren squared 2. Substitute the known values Plug the given areas ( ) and the length of side EFcap E cap F ) into the formula: