11-20.7z Here

Many "nested zip" challenges use a pattern where the filename itself is the key.

import subprocess import os filename = "11-20.7z" while True: # Attempt to extract. -p can be used if there's a known password. result = subprocess.run(["7z", "x", filename, "-y"], capture_output=True) # Logic to find the next .7z file in the directory next_files = [f for f in os.listdir('.') if f.endswith('.7z') and f != filename] if not next_files: break filename = next_files[0] print(f"Extracted: filename") Use code with caution. Copied to clipboard 11-20.7z

: Confirms it is a 7-Zip archive. If the header was missing or corrupted, you would need to manually fix the magic bytes ( 37 7A BC AF 27 1C ). Step 2: Password Extraction (The "Base64" Trick) Many "nested zip" challenges use a pattern where